4x^2-20x-132=0

Solution for 4x^2-20x-132=0 equation:

4x^2-20x-132=0

a = 4; b = -20; c = -132;
Δ = b2-4ac
Δ = -202-4·4·(-132)
Δ = 2512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2512}=\sqrt{16*157}=\sqrt{16}*\sqrt{157}=4\sqrt{157}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{157}}{2*4}=\frac{20-4\sqrt{157}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{157}}{2*4}=\frac{20+4\sqrt{157}}{8}
$